Ratio And Proportion Online Test 2020 - Aptitude Questions And Answers MCQ, Online Quiz

Solution: 1/2 * 20(9 + 6) = 150 cm2

Solution: I.(a - 3)(a - 4) = 0
=> a = 3, 4
II. (b - 2)(b - 1) = 0
=> b = 1, 2
=> a > b

Solution: Total score of the batsman in 20 matches = 800.
Total score of the batsman in the next 10 matches = 130.
Total score of the batsman in the 30 matches = 930.
Average score of the batsman = 930/30 = 31.

Solution: I. (a + 4)2 = 0 => a = -4
II.(b - 3)(b - 1) = 0
=> b = 1, 3 => a < b

Solution: (x * 8 * 1)/100 - (x * 31/4 * 1/100) = 61.50
32x - 31x = 6150 * 4
x = 24,600.

Solution: 6 * 22 = 132
7 * 19 = 133
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Solution: Let the amount lent at 7% be Rs. x
Amount lent at 10% is Rs. (6000 - x)
Total interest for one year on the two sums lent
= 7/100 x + 10/100 (6000 - x) = 600 - 3x/100
=> 600 - 3/100 x = 450 => x = 5000
Amount lent at 10% = 1000
Required ratio = 5000 : 1000 = 5 : 1

Solution: 93 + 123 + 153 = a3 => a = 18

Solution: 2 * 22/7 * 1.75 * x = 11000
x = 1000

Solution: (x*5*1)/100 + [(1500 - x)*6*1]/100 = 85
5x/100 + 90 – 6x/100 = 85
x/100 = 5
=> x = 500

Solution: P = (d * 1002) / R2
=> (48 * 100 * 100) / 8 * 8 = Rs.7500

Solution: 9 * 2 = 18 years

Solution: 20 * 10 * 5 = 1000

Solution: 2(l + 100) = 600 => l = 200 m

Solution: 6a2 = 6 * 2a * 2a = 24a2.

Solution: ---

Solution: Let sum = x. Then, amount = 7x/6
S.I. = 7x/6 - x = x/6; Time = 3 years.
Rate = (100 * x) / (x * 6 * 3) = 5 5/9 %.

Solution: Let the four integers be A, B, C and D where A > B > C > D.
(A + B + C + D)/4 = 69 => A + B + C + D = 276 ---> (1)
A = 93, D = 39 and B - C = 28
(1) => B + C = 276 - (A + D) = 276 - 132 = 144.
B + B -28 = 144
B = (144 + 28)/2 = 86

Solution: Average = (76 + 65 + 82 + 67 + 85)/5 = 375/5 = 75.

Solution: P = (184*106) / [6 2/3 * 6 2/3 *(300*6 2/3)]
P = 13500