2. I. a2  7a + 12 = 0,
II. b2  3b + 2 = 0 to solve both the equations to find the values of a and b?
 if a < b
 if a ≤ b
 if a > b
 if a ≥ b
8

View Answer
Solution:
I.(a  3)(a  4) = 0
=> a = 3, 4
II. (b  2)(b  1) = 0
=> b = 1, 2
=> a > b
3.The average runs scored by a batsman in 20 matches is 40. In the next 10 matches the batsman scored an average of 13 runs. Find his average in all the 30 matches?
 28
 29
 30
 31
11

View Answer
Solution:
Total score of the batsman in 20 matches = 800.
Total score of the batsman in the next 10 matches = 130.
Total score of the batsman in the 30 matches = 930.
Average score of the batsman = 930/30 = 31.
4. I. a2 + 8a + 16 = 0,
II. b2  4b + 3 = 0 to solve both the equations to find the values of a and b?
 If a < b
 If a ≤ b
 If a > b
 If a ≥ b
13

View Answer
Solution:
I. (a + 4)2 = 0 => a = 4
II.(b  3)(b  1) = 0
=> b = 1, 3 => a < b
5. A money lender finds that due to a fall in the annual rate of interest from 8% to 7 3/4 % his yearly income diminishes by Rs. 61.50, his capital is?
 Rs. 22,400
 Rs. 23,800
 Rs. 24,600
 Rs. 26,000
19

View Answer
Solution:
(x * 8 * 1)/100  (x * 31/4 * 1/100) = 61.50
32x  31x = 6150 * 4
x = 24,600.
6.Three years ago the average age of a family of six members was 19 years. A boy have been born, the average age of the family is the same today. What is the age of the boy?
 1 year
 1.5 years
 2 years
 2.5 years
21

View Answer
Solution:
6 * 22 = 132
7 * 19 = 133

1
7. Rs. 6000 is lent out in two parts. One part is lent at 7% p.a simple interest and the other is lent at 10% p.a simple interest. The total interest at the end of one year was Rs. 450. Find the ratio of the amounts lent at the lower rate and higher rate of interest?
 5 : 1
 4 : 1
 3 : 2
 2 : 1
25

View Answer
Solution:
Let the amount lent at 7% be Rs. x
Amount lent at 10% is Rs. (6000  x)
Total interest for one year on the two sums lent
= 7/100 x + 10/100 (6000  x) = 600  3x/100
=> 600  3/100 x = 450 => x = 5000
Amount lent at 10% = 1000
Required ratio = 5000 : 1000 = 5 : 1
8. Three cubes of metal whose edges are 9, 12 and 15 cm respectively, are melted and one new cube is made. Find the edge of the new cube?
 18 cm
 19 cm
 21 cm
 32 cm
29
9. The radius of a circular wheel is 1.75 m, how many revolutions will it make in traveling 1 km?
 1000
 2000
 3000
 4000
33

View Answer
Solution:
2 * 22/7 * 1.75 * x = 11000
x = 1000
10. Rs.1500 is divided into two parts such that if one part is invested at 6% and the other at 5% the whole annual interest from both the sum is Rs.85. How much was lent at 5%?
 Rs.1000
 Rs.750
 Rs.600
 Rs.500
40

View Answer
Solution:
(x*5*1)/100 + [(1500  x)*6*1]/100 = 85
5x/100 + 90 – 6x/100 = 85
x/100 = 5
=> x = 500
11. A person got Rs.48 more when he invested a certain sum at compound interest instead of simple interest for two years at 8% p.a. Find the sum?
 Rs. 6500
 Rs.7000
 Rs.7500
 Rs.8000
43

View Answer
Solution:
P = (d * 1002) / R2
=> (48 * 100 * 100) / 8 * 8 = Rs.7500
12.The average age 9 members of a committee are the same as it was 2 years ago, because an old number has been replaced by a younger number. Find how much younger is the new member than the old number?
 7 years
 12 years
 18 years
 27 years
47
14.If the perimeter of a rectangular garden is 600 m, its length when its breadth is 100 m is?
 650 m
 600 m
 300 m
 200 m
56
16. A man walked 20 m to cross a rectangular field diagonally. If the length of the field is 16 cm. Find the breadth of the field is?
 11 m
 12 m
 13 m
 14 m
62
17. A sum of money becomes 7/6 of itself in 3 years at a certain rate of simple interest. The rate per annum is?
 5 5/9 %
 6 5/9 %
 18%
 25%
65

View Answer
Solution:
Let sum = x. Then, amount = 7x/6
S.I. = 7x/6  x = x/6; Time = 3 years.
Rate = (100 * x) / (x * 6 * 3) = 5 5/9 %.
18. The average of four positive integers is 69. The highest integer is 93 and the least integer is 39. The difference between the remaining two integers is 28. Which of the following integers is the higher of the remaining two integers?
 68
 86
 90
 99
70

View Answer
Solution:
Let the four integers be A, B, C and D where A > B > C > D.
(A + B + C + D)/4 = 69 => A + B + C + D = 276 > (1)
A = 93, D = 39 and B  C = 28
(1) => B + C = 276  (A + D) = 276  132 = 144.
B + B 28 = 144
B = (144 + 28)/2 = 86
19. Dacid obtained 76, 65, 82, 67 and 85 marks (out of 100) in English, Mathematics, Physics, Chemistry and Biology. What are his average marks?
 65
 69
 72
 75
76

View Answer
Solution:
Average = (76 + 65 + 82 + 67 + 85)/5 = 375/5 = 75.
20.The difference between compound and simple interest on a certain sum of money for 3 years at 6 2/3% p.a is Rs.184. Find the sum?
 Rs.12000
 Rs.14200
 Rs.17520
 Rs.13500
80

View Answer
Solution:
P = (184*106) / [6 2/3 * 6 2/3 *(300*6 2/3)]
P = 13500