Ratio And Proportion Online Test 2020 - Aptitude Questions And Answers MCQ, Online Quiz

Solution: Ratio 8:11:13
No of men, women and boys are 6, 5, 3
Then ratio of men, women and boys 6*8 : 5*11 : 13*3
=48:55:39
Men part is= (48/142)* 1278 = 432
Then 1 man part= 432/6 =72

Solution: To buy maximum chocolates we must buy Rs 2 choclate more.
10*1=10
5*2=10(we can’t buy one chocolate from Rs 5 because we have amount in even no )
2*60=120
Total chocolate (1+2+60)=63.
To buy minimum chocolates we must buy Rs 10 choclate more.
2*5=10
5*2=10(we can’t buy one chocolate from Rs 5 because we have amount in even no )
10*12=120
Total chocolate (5+2+12)=19.

Solution: Two can has equal capacity. So we consider 10litre in each can. 1st can (5+3) 8 10 Milk 5 ===> 25/4L Water 3 ===>15/4L 2nd can (4+3) 7 10 Milk 4 ===> 40/7L Water 3 ===>30/7L Then New ratio M+M 25/4 +40/7 : W+W 15/4+30/7 335/28: 225/28=67:45

Solution: Let the number of failed students be x Number of passed students = 4x So total number of students was 5x From the given data If total number of students be 5x – 35 (5x-35)/x+9=3/1 x = 31 Total number = 31×5 = 155

Solution: 8M+3B=4(1M+1B) 8M+3B=4M+4B 4M=B B:M=4:1

Solution: Given C+D= (A+B)/2 B:C 3:1 C:D 3:5 B:C:D 9:3:5 (A+B)=2(C+D) A+9x=2(3x+5x) A=7x. Total (7+9+3+5) 24 x=1440==>x=60 Then 7x=7*60==>420

Solution: The ratio of broken part 3:4:5 Value of broken parts of diamond =3x2 +4x2+5x2=50x2 Value of original diamond 12x2=144x2 Then loss= 144x2-50x2=94x2 94x2=9.4Lakh Actual value= 144x2=144 *9.4/94 =14.4Lakh

Solution: Weight of Mango and Apple 5:6 Apple 6 180gm Mango 5 150gm Grape 35gm Ratio 2:5:7 Required ratio of fruits by weight =2*150 : 5*180 : 7*35 =60:180:49.

Solution: Dog/Cat = 5/4 Let cat’s 1 leap = 4 meter and dogs 1 leap = 5 meter. Then, ratio of speed of cat and dog = 4*6/5*4 = 24:20==>6:5.

Solution: Let the original number of students be 8x, 9x and 11x (8x + 15)/(9x + 15)=11/12 12(8x+15) =11(9x+15) 96x+180=99x+165 3x=15 x = 5 Required number of students = 8x + 9x + 11x = 28x = 28*5 = 140

Solution: Let the number of students in the classes be 6x, 7x and 8x respectively; Total students = 6x+7x+8x = 21x. Then (6x+15)/(7x+15)=9/10 60x+150=63x+135 X=5. Total students =21*5=105.

Solution: Zinc in Alloy A=4/9 Zinc in Alloy B=6/13 Sulphur in Alloy A=5/9 Sulphur in Alloy B=7/13 Then in alloy C Zinc : Sulphur 4/9+6/13 : 5/9+7/13 106/117: 128/117 =53:64.

Solution: 5/8 part filled in 1 minute full filled in 8/5 minute so remaining 3/8 will filled in (8/5)*(3/8) = 3/5 minute = 36 seconds .

Solution: Quantity of milk and water in the 36 liter mixture; 27 liter milk and 9 liter water. Now, 15 liters milk is added then milk becomes 42 liters. Now, ratio = 42:9 = 14:3.

Solution: Data Inadequate.

Solution: Let bucket contains 5x and 3x of liquids A and B respectively. When 16 litres of mixture is replaced, A and B has a mixture is [5x – (5/8)*16] = (5x – 10) [3x – (3/8)*16] = (3x – 6) Ratio (5x – 10)/(3x – 6+16) = 3/5 (5x – 10)/(3x +10) = 3/5 X=5. So, quantity of liquid B initially, = 3*5 = 15 litres.

Solution: Let the two positive numbers be 5x and 3x respectively. 5x-3x = 10 x = 5. Then numbers are 25 and 15. Thus, their product = 25*15 = 375.

Solution: Let Guna’s and Shekar’s present age is 6x and 5x respectively. then (6x+12)/(7x+12) = 8/9 54x+108 = 56x + 96 2x = 12 x = 6 Present age of Guna = 6x = 36.

Solution: Ratio 43:47 Average 135 Then Total=2*135=270. Deer=270*47/90 =141.

Solution: Let the total population be 'p' Male :Female 7 : 8 Percentage of children among male and female is 25% and 20% Then Adults male and female % = 75% & 80% => 80%(8p/15) = 156800 => 80 x 8p/15 x 100 = 156800 => p = 156800 x 15 x 100/80 x 8 => p = 367500 Therefore, the total population of the city = p = 367500.